Question

How Raoult's Law useful in determining the molecular weight of non volatile and non electrolyte solute?

Answer 1

Explanation:

Raoult's law states that the relative lowering of vapour pressure of a solution containing a nonvolatile solute is equal to the mole fraction of the solute in the solution.

Answer 2

$\frac{P^0-P_s}{P^0}=x_B=\frac{n_2}{n_1+n_2}$

Explanation:

Raoult's law for non- volatile and non- electrolyte solute:

It states that the relative lowering in vapour pressure of a solution containing a non volatile solute is equal to mole fraction of solute in the solution.

Mathematically representation:

$\frac{P^0-P_s}{P^0}=x_B=\frac{n_2}{n_1+n_2}$

Where $P^0$=Vapour pressure of pure solvent

$P_s$=Vapour pressure of solution

$x_B$=Mole fraction of solute

$n_2$=Number of moles of solute

$n_1$=Number of moles of solvent

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