How should I explain Aharonov-Bohm effect in QED?
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Hey dear here is the answer
Because E = B = 0 outside of an infinite solenoid the associated Aharanov-Bohm vector potential is unaffected by EM quantization performed in the Coulomb gauge, leaving the traditional single-particle Schrodinger / QM analysis intact.
Hope its help you
Because E = B = 0 outside of an infinite solenoid the associated Aharanov-Bohm vector potential is unaffected by EM quantization performed in the Coulomb gauge, leaving the traditional single-particle Schrodinger / QM analysis intact.
Hope its help you
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.Aharonov-Bohm effect in QED states E=B=0 outside infinite solenoid that indicates the current passage faster.
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