how sin 2 theta is equal to 2sin theta cos theta
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Question:
=> Prove that sin 2Ф = 2 sinФ cosФ
Solution:
We know:
=> sin(A + B) = sinA cos B + cosA sinB
Using it we get:
=> sinФ cosФ + cosФ sinФ
=> 2(sinФ.cosФ)
=> 2 sinФ cosФ
Hence, L.H.S = R.H.S.
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