how solve this problem (243)2/5
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![(243 )^{ \frac{2}{5} } \\ \\ = { ({3}^{5} ) }^{ \frac{2}{5} } \: \: \: \: \: \: \:(Since, \: \: 243 = {3}^{5} ) \\ \\ = {3}^{(5 \times \frac{2 }{5} )} \: \: \: \: \:[\:Since, \:{( a {}^{m} ) }^{n} =( a) {}^{m \times n} \:]\\ \\ = {(3)}^{2} \\ \\ = 9](https://tex.z-dn.net/?f=%28243+%29%5E%7B+%5Cfrac%7B2%7D%7B5%7D+%7D+%5C%5C+%5C%5C+%3D+%7B+%28%7B3%7D%5E%7B5%7D+%29+%7D%5E%7B+%5Cfrac%7B2%7D%7B5%7D+%7D+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A%28Since%2C+%5C%3A+%5C%3A+243+%3D+%7B3%7D%5E%7B5%7D+%29+%5C%5C+%5C%5C+%3D+%7B3%7D%5E%7B%285+%5Ctimes+%5Cfrac%7B2+%7D%7B5%7D+%29%7D+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A%5B%5C%3ASince%2C+%5C%3A%7B%28+a+%7B%7D%5E%7Bm%7D+%29+%7D%5E%7Bn%7D+%3D%28+a%29+%7B%7D%5E%7Bm+%5Ctimes+n%7D+%5C%3A%5D%5C%5C+%5C%5C+%3D+%7B%283%29%7D%5E%7B2%7D+%5C%5C+%5C%5C+%3D+9 "(243 )^{ \frac{2}{5} } \\ \\ = { ({3}^{5} ) }^{ \frac{2}{5} } \: \: \: \: \: \: \:(Since, \: \: 243 = {3}^{5} ) \\ \\ = {3}^{(5 \times \frac{2 }{5} )} \: \: \: \: \:[\:Since, \:{( a {}^{m} ) }^{n} =( a) {}^{m \times n} \:]\\ \\ = {(3)}^{2} \\ \\ = 9")
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