Question

How terms are there in the AP 7,13,19......205?

Answer 1

Answer:

205=7+(n-1)*6

205=7+6n-6

204=6n

n=34

Answer 2

Step-by-step explanation:

Given sequence is 7,13,19,...,205

The first term a=7 and

The common difference d=13−7=6

Let the last term be the n th term. We know that the nth term of the arithmetic progression is given by a+(n−1)d

Therefore, a+(n−1)d=205 ⟹7+(n−1)×(6)=205

7+(n−1)×(6)=205⟹7−6+6n=205

⟹1+6n=205

⟹6n=205−1

⟹6n=205−1⟹n= 204/6

⟹1+6n=205⟹6n=205−1⟹

n=204/6⟹n=34

Therefore, the number of terms in the given sequence is 34