how that AB CD
5.
ABCD is a quadrilateral in which all the four angles are equal. Show that
and AD || BC.
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<A = <B = <C = <D
let them be x
x+x+x+x = 360° (ASP of quad)
4x = 360°
x = 90°
Hence all angles are of 90°
This means the figure is a either a rectangle or a square and opposite sides of rectangles and squares are parallel.
Therefore AD || BC
let them be x
x+x+x+x = 360° (ASP of quad)
4x = 360°
x = 90°
Hence all angles are of 90°
This means the figure is a either a rectangle or a square and opposite sides of rectangles and squares are parallel.
Therefore AD || BC
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