Question

how the 0+0 is 2 give explanation

Answer 1

Hey there!

Actually, This isn't correct 0 + 0 = 0 , But not 2 , as you have asked I am giving you a proof.

0 - 0 = 0 - 0

0² - 0² = 0*2 - 0*2

( 0 + 0 ) ( 0 - 0 ) = 2 ( 0 - 0 )

( 0 + 0 ) = 2 .


Hope helped!

Answer 2

The answer is given below :

We know that,

0 - 0 = 0 - 0

⇒ 0² - 0² = 0×2 - 0×2

⇒ (0 + 0) (0 - 0) = 2 × (0 - 0),
using the identity a² - b² = (a +b)(a - b)

⇒ 0 + 0 = 2

So, 0 + 0 = 2 [Proved]

THE MISTAKE :

We know that if x be a non-zero real number, then to make a resulting multiplicative identity (1) in purpose, we need to multiply x by its reciprocal.

Let me give an example of how cancellation law works in multiplication.

a = b

Now, to make the RHS = 1, we need to multiply both sides with the reciprocal of b, i.e., 1/b, where b ≠ 0 because if b = 0, (1/0) be undefined.

Thus in the given problem, we cancelled (0 - 0) = 0, by multiplying both sides with the reciprocal of 0, i.e., 0^(-1) = 1/0, which is undefined.

But in these types of proofs, this kind of committed mistake in purpose is ignored.

Thank you for your question.