Question

How the following is right
$(a + b)^{2} = {a}^{2} + 2ab + {b}^{2}$
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Answer 1

Let us take the value of 'a' as 1 and 'b' as 2

(a+b)² = a² + 2ab + b²

(1+2)² = (1)² + 2(1)(2) + (2)²

(3)² = 1+4+4

9=9

Therefore, we can conclude that

(a+b)² = a² + 2ab + b²

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Answer 2

Step-by-step explanation:

$( {a + b})^{2} \\ (a + b)(a + b) \\ a(a + b) + b(a + b) \\ {a}^{2} + ab + ba + {b}^{2} \\ {a}^{2} + ab + ab + {b}^{2} \\ {a}^{2} + 2ab + {b}^{2}$