Question

how the frequency of vibrating wire is affected if the load is fully immersed in water?

Answer 1

Answer:

When the attached load is immersed in water, the apparent weight decreases. Therefore, tension T in string decreases. v=12l√Tm decreases.

Answer 2

The frequency of vibrating wire is greater than the frequency of the wire when the load is fully immersed in water.

Explanation:

The frequency is given by the formula:

F = 1/2L √(T/μ)

Where,

L = Length of the wire

μ = Linear mass density of the wire

T = Tension of the wire = mg

F = 1/2L √(mg/μ)

If the load is fully immersed in water, the tension of the wire is:

T' = Mg - F

T' = Mg - Vρg

The frequency when the load is fully immersed in water is:

F' = 1/2L √(T'/μ)

F' = 1/2L √((Mg - Vρg)/μ)

∴ F' < F

Thus, the frequency of the wire with load when fully immersed in water is less than the frequency of the vibrating wire.