how the frequency of vibrating wire is affected if the load is fully immersed in water?
Answers
Answered by
6
Answer:
When the attached load is immersed in water, the apparent weight decreases. Therefore, tension T in string decreases. v=12l√Tm decreases.
Answered by
8
The frequency of vibrating wire is greater than the frequency of the wire when the load is fully immersed in water.
Explanation:
The frequency is given by the formula:
F = 1/2L √(T/μ)
Where,
L = Length of the wire
μ = Linear mass density of the wire
T = Tension of the wire = mg
F = 1/2L √(mg/μ)
If the load is fully immersed in water, the tension of the wire is:
T' = Mg - F
T' = Mg - Vρg
The frequency when the load is fully immersed in water is:
F' = 1/2L √(T'/μ)
F' = 1/2L √((Mg - Vρg)/μ)
∴ F' < F
Thus, the frequency of the wire with load when fully immersed in water is less than the frequency of the vibrating wire.
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