how the resistance of a wire affected if its radius is doubled
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= pl/A, where R is resistance, p is the material's resistance in ohms, l is the length, and A is the cross sectional area in m^2. As a wire gets longer its resistance increases, and as it gets thinner its resistance also increases because its cross sectional area decrease
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-------------------------------------HEY DEAR----------------------------------
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HERE IS YOUR ANSWER............
RESISTANCE IS INVERSELY PROPORTIONAL TO SQAURE OF THE RADIUS ..
THE FORMULA IS ATTACHED WITH THE ANSWER IN THE FOLLOWING ATTACHMENT .. SO, IF RADIUS IS DOUBLED THEN
RESISTANCE = 1/ R^2
RESISTANCE = 1 / 4R
SO, IF WE INCREASE THE RADIUS BY DOUBLED THEN RESISTANCE WILL BE ONE- FOURTH
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