Question

How the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres?

Answer 1

Mole = Volume/22.4 (At S.T.P or N.T.P.)

thus we can say since 1 mole of O2 or 2 mole atoms of oxygen occupies = 22.4 litres at N.T.P. therefore 1 mole atom of oxygen occupies = 22.4/2 = 11.2 litres at N.T.P. =11.2 litre.