How the volume of a resistance of conductor be change if its length is increased two time of its previous length ?
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length of the conductor is directly proportional to the resistance so if the length is doubled the resistance will also increase
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Thanks for requesting.
We have
Resistance= Resistivity x length/area
When the wire is stretched to double the length , the area of cross section gets reduced to half.
So
New Resistance = Resistivity x 2length/area/2
I.e,
New resistance = (Resistivity x area/length)x4
i.e, New resistance = Resistance×4
So when the wire is stretched, the resistance multiplies by four times.
Hope you understood. Keep exploring.
Edit: To understand why area gets halved when length is doubled
hope it helps you!!!
mark me as brainlist!!!
#$hreya
We have
Resistance= Resistivity x length/area
When the wire is stretched to double the length , the area of cross section gets reduced to half.
So
New Resistance = Resistivity x 2length/area/2
I.e,
New resistance = (Resistivity x area/length)x4
i.e, New resistance = Resistance×4
So when the wire is stretched, the resistance multiplies by four times.
Hope you understood. Keep exploring.
Edit: To understand why area gets halved when length is doubled
hope it helps you!!!
mark me as brainlist!!!
#$hreya
Broo00:
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