Question

how the zeros of the polynomial x square - 7x + 12 are
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Answer 1

Note:

To find the zeros of a polynomial, equate it to zero.

Here,

The given quadratic polynomial is;

x^2 - 7x + 12.

Hence, to get the zeros of the given polynomial, equate it to zero.

ie;

=> x^2 - 7x + 12 = 0

=> x^2 - 4x - 3x + 12 = 0

=> x(x - 4) - 3(x - 4) = 0

=> (x - 4)(x - 3) = 0

=> (x - 4) = 0 OR (x - 3) = 0

=> x = 4 OR x = 3

Hence,

The zeros of the given polynomial are

4 and 3.

Answer 2

Answer:-

Zeros of this polynomial are 3 and 4

Step - by - step explanation:-

Find :-

Find zeros of the given polynomial

Given polynomial:-

${x}^{2} - 7x + 12 = 0 \\ \\ \implies \: {x}^{2} - 4x - 3x + 12 = 0 \\ \\ \implies \: x(x - 4) - 3(x - 4) = 0 \\ \\ \implies \: (x - 4)(x - ) = 0 \\ \\ \star \: \: if \: x - 4 = 0 \\ \: \: \green{ x = 4 }\\ \\ \star \: \: if \: x - 3 = 0 \\ \: \red{\: x = 3}$

Hope it helps you.