how to ad from 1 to 100
Answers
Answered by
5
Just use the formula
Sn=n/2(2a+(n-1)d)
Given n=100
a =1
d =1
Sn= 100/2(2x1+(100-1)1)
Sn=50x101
Sn=5050
Do follow and mark as brainliest
Sn=n/2(2a+(n-1)d)
Given n=100
a =1
d =1
Sn= 100/2(2x1+(100-1)1)
Sn=50x101
Sn=5050
Do follow and mark as brainliest
Answered by
6
8Here is your answer !!
____________________________
According to Carl's Gause method !!
No. in increasing order :
1 2. 3. 4. 5. 6. ...............100
No. in decreasing order :
100. 99. 98. 97. 96. ............. 1
Now add it , we get
101. 101. 101. 101. ..................101
This sums occurs 100s time , therefore multiply it by 100 we get
100 x 101 = 10100
In this 1 to 100 counted two times therefore, half of this is
10100/2 = 5050 and this is answer !
So, according to this theory a simple formula were discovered to find the sum of any number s and that is,
Sn = n/2[2a + (n-1)d]
We have ,
1,2,3,4.......100
Here,
a = 1
d = 1
n = 100
Put the given values
S₁₀₀ = 100/2[ 2 x 1(100-1)1]
S₁₀₀ = 50 x 101
∴ S₁₀₀ = 5050
∴ The sum of all numbers from 1 to 100 is 5050 .
Thanks !!
____________________________
According to Carl's Gause method !!
No. in increasing order :
1 2. 3. 4. 5. 6. ...............100
No. in decreasing order :
100. 99. 98. 97. 96. ............. 1
Now add it , we get
101. 101. 101. 101. ..................101
This sums occurs 100s time , therefore multiply it by 100 we get
100 x 101 = 10100
In this 1 to 100 counted two times therefore, half of this is
10100/2 = 5050 and this is answer !
So, according to this theory a simple formula were discovered to find the sum of any number s and that is,
Sn = n/2[2a + (n-1)d]
We have ,
1,2,3,4.......100
Here,
a = 1
d = 1
n = 100
Put the given values
S₁₀₀ = 100/2[ 2 x 1(100-1)1]
S₁₀₀ = 50 x 101
∴ S₁₀₀ = 5050
∴ The sum of all numbers from 1 to 100 is 5050 .
Thanks !!
niti13:
#Amazing Answer
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