Question

how to balance equation of Mg+H²O=MgSO⁴+H2
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Answer 1

Answer:

As we know that,

No. of moles=mol. wt.wt.

Now,

Wt. of Mg=6g

Mol. wt. of Mg=24g

No. of moles of Mg in 6g=246=0.25 moles

Mg+H2SO4⟶MgSO4+H2

from the above reaction,

1 mole of magnesium sulphate is formed when 1 mole of magnesium reacts.

Therefore,

0.25 mole of magnesium sulphate is formed when 0.25 mole of magnesium reacts.

Now,

Mol. wt. of MgSO4=120g

Therefore,

Wt. of 0.25 moles of MgSO4=0.25×120=30g

Hence 30g of magnesium sulphate is formd when 6g of magnesium reacts with excess of H2SO4.

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