Question

How to balance the chemical
mno2+hcl_mncl2 +cl2 + h2o

Answer 1

skeleton equation

MnO2 + HCl --------> MnCl2 + Cl2 + H2O

First we will count the number of molecule in both the side

◆ LHS (Left hand side ) or reactant

Mn = 1

O = 2

H = 1

Cl = 1

◆ RHS ( Right hand side ) or product

Mn = 1

O = 1

H = 2

Cl = 4

first we will balance Cl

MnO2 + 4HCl ------> MnCl2 + Cl2 + H2O

◆ now , LHS (Left hand side ) or reactant

Mn = 1

O = 2

H = 4

Cl = 4

◆ RHS ( Right hand side ) or product

Mn = 1

O = 1

H = 2

Cl = 4

Now, we will balance hydrogen

MnO2 + 4HCl -------> MnCl2 + Cl2 + 2H2O

◆ LHS (Left hand side ) or reactant

Mn = 1

O = 2

H = 4

Cl = 4

◆ RHS ( Right hand side ) or product

Mn = 1

O = 2

H = 4

Cl = 4

equation is balanced

Balanced equation

MnO2 + 4HCl -------> MnCl2 + Cl2 + 2H2O