Question

how to balance the equation C+H2SO4= CO2+H20+SO2

Answer 1

Hi there !

$C + H_{2}SO_{4} \longrightarrow CO_{2} + H_{2}O + SO_{2}$


Step-1:

Check No. of Atoms of each element in LHS and RHS of the reaction

In LHS,

(The reactants)

$C + H_{2}SO_{4}$

C - 1

H - 2

S - 1

O - 4

In RHS,

(The products)

$CO_{2} + H_{2}O + SO_{2}$

C - 1

H - 2

S - 1

O - 5



Step-2:

From above, it's clear that only H and O are unbalanced.

In LHS, we need to modify the 2nd term i.e., $H_{2}SO_{4}$

i.e., change the no. of it's molecules

$C + 2H_{2}SO_{4}$

In LHS,

(The reactants)

$C + 2H_{2}SO_{4}$

C - 1

H - 4

S - 2

O - 8



Step-3:

As there are 4 Hydrogen available, it can combine with 2 oxygen to result 2 molecules of Water i.e $2H_{2}O$

$C + 2H_{2}SO_{4} \longrightarrow CO_{2} + 2H_{2}O + SO_{2}$

In LHS,

(The reactants)

$C + 2H_{2}SO_{4}$

C - 1

H - 4

S - 2

O - 8

In RHS,

(The products)1

$CO_{2} + 2H_{2}O + SO_{2}$

C - 1

H - 4

S - 1

O - 6



Step-4:

It is observed that S and O are unbalanced and these combinely form $SO_{2}$ as in the products. Need to change the no. of molecules of $SO_{2}$

As 2 S are available, change it to $2SO_{2}$

And Now,

In RHS,

(The products)1

$CO_{2} + 2H_{2}O + 2SO_{2}$

C - 1

H - 4

S - 2

O - 8

Thus, reaction is now balanced



$\huge{ \fbox{ \mathbf{C + 2H_{2}SO_{4} \longrightarrow CO_{2} + 2H_{2}O + 2SO_{2} }}}$




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Answer 2

ANSWER

In this equation with Carbon another element is missing