how to bisect 75 degree angle
please help it's as urgent as an occurrence of earthquake
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step 1. draw a line segment BC of any length.
step2. construct angle OBC = 60 degree and an angle PBC = 90 degree.
step 3. now angle OBP = 9O - 60 = 30 degree. bisect angle OBP.( with B as a centre and a suitable radius draw an arc that cuts PB and OB at D and E respectively.now with D as a centre and with same radius draw an arc.now with E as a centre and with same radius draw another arc.let the arcs meet at F. join B and F and produce it to A. ABC is the required angle.)
step4. now bisect angle ABC similarly.
step2. construct angle OBC = 60 degree and an angle PBC = 90 degree.
step 3. now angle OBP = 9O - 60 = 30 degree. bisect angle OBP.( with B as a centre and a suitable radius draw an arc that cuts PB and OB at D and E respectively.now with D as a centre and with same radius draw an arc.now with E as a centre and with same radius draw another arc.let the arcs meet at F. join B and F and produce it to A. ABC is the required angle.)
step4. now bisect angle ABC similarly.
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