how to caculate largest no. of atoms
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no.of atoms =no.of moles x avagadro no x no.of atom of that element
nannurasheed:
ok
example question: Find the no of oxygen atoms present in 5moles of glucose (C6H12O6)
answer: no.of atoms =no.of moles x avagadro no x no.of atom of that element ie, no of atoms=5x6.022x10^23 x6
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