Chemistry, asked by neerajsemwal3925, 10 months ago

How to calculate (288×10^-10)^3

Answers

Answered by ItZvIsH

10

288^3 × 10^-10×3

= 23887872 × 10^-30

=2.3887872× 10^-23

Previous Question

Next Question

Similar questions

Sociology, 5 months ago

______gave a shape to the study of political science ...

Science, 5 months ago

CII Slalli Un a cloth becomes reddish while washir omen.o...is an indicatos...and. 5.00p.is. o the stunmemps. Stein...eith..soap the dish.brown.co...colours because when... base.it tatne the colour of the bas How will you find out whether the soil is fertile or not using a the copper p...

India Languages, 5 months ago

Combine each pair of simple sentences into one complex sentence containing a noun clause 4. He is mad. That makes him more dangerous. 5. He may be innocent. I don’t know. 6. The game was lost. It was the consequence of his carelessness. 7. Where have you put my hat? Tell me. 8. We have been deceived. That is the truth.

English, 10 months ago

please answer for this question very urgent ...

Art, 10 months ago

What is the largest spelling in the world...

Physics, 1 year ago

A man weighing 80 kg is standing on a trolley weighing 320 kg. The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley along the rails at a speed of one metre per second, then after 4 seconds, his displacement relative to the ground will be :(a) 5 metres (b) 4.8 metres(c) 3.2 metres (d) 3.0 metres...

Physics, 1 year ago

Two mass m and 2m are attached with each other by a rope passing over a frictionless and massless pulley. If the pulley is accelerated upwards with an acceleration ‘a’, what is the value of T? (a) $\frac{g+a}{3}$ (b) $\frac{g-a}{3}$ (c) $\frac{4m(g+a)}{3}$ (d) $\frac{m(g-a)}{3}$ ...

Physics, 1 year ago

A particle of mass 10 kg is moving in a straight line. If its displacement, x with time t is given by x = (t³ – 2t – 10) m, then the force acting on it at the end of 4 seconds is(a) 24 N (b) 240 N(c) 300 N (d) 1200 N...