How to calculate amount of oxygen required to burn?
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calculate how much amount of air is needed to burn the fuel .
Let's take Petrol… its range is 14.7 : 1 ratio for combustion .
Which means for Petrol 14.7 gram of air required for burning 1 gram of fuel . For complete combustion it varies according to the efficiency of fuel , economically in-complete combustion. So it differs from fuel to fuel varies ratios according to the fuel density .
Intake pressure /temperature/ Fuel …. considering all aspects.
Just simple method.
Let's take Petrol… its range is 14.7 : 1 ratio for combustion .
Which means for Petrol 14.7 gram of air required for burning 1 gram of fuel . For complete combustion it varies according to the efficiency of fuel , economically in-complete combustion. So it differs from fuel to fuel varies ratios according to the fuel density .
Intake pressure /temperature/ Fuel …. considering all aspects.
Just simple method.
Namrah4:
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Hey there, here's your answer buddy
- 1 mole of Carbon combines with 1 mole of molecular oxygen to form carbon dioxide.
- 1 mole of carbon weighs 12 grams. Hence 36 grams indicates there are 3 moles of carbon. One mole of molecular oxygen weighs 32 grams and its volume should be 22.4 liters at STP. Hence we require 3 moles of molecular oxygen to burn completely with 3 moles of carbon.
- Hence we require about 22.4 x 3 = 67.2 liters of molecular oxygen.
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