How to calculate area of parallelogram with vector?
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hint towards exams.
Area=|a⃗ ×b⃗ |Area=|a→×b→|
|a⃗ ×b⃗ ||a→×b→|
=
∣∣∣∣i−1−2j0−2k22∣∣∣∣|ijk−102−2−22|
now that we got our tangent vector specified,
∣∣∣0−222∣∣∣i−∣∣∣−1−222∣∣∣j+∣∣∣−1−202∣∣∣k|02−22|i−|−12−22|j+|−10−22|k
∴ your equation of line should be;
4i−(−2+4)j+2k=4i+2j+2k4i−(−2+4)j+2k=4i+2j+2k
Thus Area =
|a⃗ ×b⃗ |=42+22+22−−−−−−−−−−√=24−−√|a→×b→|=42+22+22=24
Hope this helps you.
Area=|a⃗ ×b⃗ |Area=|a→×b→|
|a⃗ ×b⃗ ||a→×b→|
=
∣∣∣∣i−1−2j0−2k22∣∣∣∣|ijk−102−2−22|
now that we got our tangent vector specified,
∣∣∣0−222∣∣∣i−∣∣∣−1−222∣∣∣j+∣∣∣−1−202∣∣∣k|02−22|i−|−12−22|j+|−10−22|k
∴ your equation of line should be;
4i−(−2+4)j+2k=4i+2j+2k4i−(−2+4)j+2k=4i+2j+2k
Thus Area =
|a⃗ ×b⃗ |=42+22+22−−−−−−−−−−√=24−−√|a→×b→|=42+22+22=24
Hope this helps you.
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