Question

how to calculate breakdown voltage

Answer 1

• In electronics applications, with small voltages, capacitors have the order of picofarads or nano farads. The width of dielectric medium in between conducting terminals of the capacitors is about 0.01mm 0.1 mm... Hence the breakdown voltage will be: 2 * 10^6 * 0.01 *10^-3 = 20 volts to 200 volts

Answer 2

Answer:

In electronics applications, with small voltages, capacitors have the order of picofarads or nano farads. The width of dielectric medium in between conducting terminals of the capacitors is about 0.01mm 0.1 mm... Hence the breakdown voltage will be: 2 * 10^6 * 0.01 *10^-3 = 20 volts to 200 volts.

Explanation:

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