Question

How to calculate equilibrium constant of rate constant for forward and backward reaction is given?

Answer 1

Explanation:

let two reactant A and B change into C and D.

aA+bB-cC+dD

let rate of forward reaction be

r1 =kf(A)^a(B)^b

rate of backward reaction be

r2 = kb(C)^c(D)e

at equilibrium

r1=r2

kf(A)^a(B)^b=kb(C)^c(D)^d

kf/kb = kc=(C)^c(D)d/(A)^a(B)^b