Question

How to calculate equivalent weight of na2co3?

Answer 1

Answer:

its simple....

Step-by-step explanation:

The salt Na2CO3 ionizes to form 2Na+ and CO3(–2). So, the charge present on both

ions is 2.

Equivalent weight of Na2CO3 = 106 /2 = 53 g/eq

Answer 2

Answer:

53g/ey

Step-by-step explanation:

before we know the explanation of the topic , let us know what equivalent weight is

the equivalent weight  is defined as the ratio of the molecular weight of the solute to the valency of the solute. The equivalent weight of a chemical solution or of the substance will vary , and it completely depends on the types of reactions it undergoes.

It is generally used to predict the mass of the substance which reacts with the one atom of hydrogen in the acid-base analysis. Also, the normality of the solution can be calculated using the equivalent weight. It means that the normality of the chemical solution is defined as the number of the equivalent weight of any substance dissolved in the one litre of solution. The formula to calculate the equivalent weight is given as:

$Equivalent weight = Molecular weight/ Valency$

$E = MW/charge number$

steps to calculate:

Step 1: formula of equivalent weight

Step 2: Calculation of the molecular mass for $na2co3$

Step 3; Calculation of the equivalent weight for $na2co3$

$2 (Na) + (C) + 3(O) = 2 (23) + (12) + 3(16) = 46 + 12 + 48 = 106.$

The sulfuric acid $Na2CO3‘s$ molecular mass is $106 g/mol.$

Equivalent weight of $Na2CO3$

$= 106/2$

$= 53 g/eq.$

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