How to calculate equivalent weight of sodium carbonate?
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Molecular formula of sodium carbonate : Na₂CO₃
So, molecular weight = 2 × 23 + 12 × 3 × 16 = 106 g/mol
Here we can observe : Na₂CO₃ ⇔ 2Na⁺ + CO₃⁻⁻
Hence, n - factor = change in oxidation number = 2 - 0 = 2
So, equivalent weight = molecule weight/n-factor = Molecular weight/2
This way , equivalent of Na₂CO₃ = 106/2 = 53
But you said 62 , how much increment 62 - 53 = 9
Means a mole of hydroxide {H₂O} is attached with it. Or you can say sodium carbonate is hydrated .
Now, see Na₂CO₃.H₂O , M.weight = 106 + 18 = 124 g/mol
So, equivalent weight = 124/2 = 62
Hence, here sodium carbonate is present with water e.g., Na₂CO₃.H₂O
So, molecular weight = 2 × 23 + 12 × 3 × 16 = 106 g/mol
Here we can observe : Na₂CO₃ ⇔ 2Na⁺ + CO₃⁻⁻
Hence, n - factor = change in oxidation number = 2 - 0 = 2
So, equivalent weight = molecule weight/n-factor = Molecular weight/2
This way , equivalent of Na₂CO₃ = 106/2 = 53
But you said 62 , how much increment 62 - 53 = 9
Means a mole of hydroxide {H₂O} is attached with it. Or you can say sodium carbonate is hydrated .
Now, see Na₂CO₃.H₂O , M.weight = 106 + 18 = 124 g/mol
So, equivalent weight = 124/2 = 62
Hence, here sodium carbonate is present with water e.g., Na₂CO₃.H₂O
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