How to calculate for 0.01m sulphuric acid?
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Hi,
pH of any acid can be calculated by using the following formula:
pH= -log(H+) Here H+ refers to the concentration of H+ ions or the Hydronium ions.
Firstly we need to see the disociation of H2SO4 in water:
H2SO4(aq)————→ 2H+(aq) + (SO4)^2-(aq)
Here it can be clearly observed that 1 moles of sulphuric acid gives rise to 2 moles of H+ ions.
Therefore, 0.01 moles of H2SO4 will give rise to 0.02 moles of H+ ions
Substituting the value of H+ in the formula,
pH=-log(0.02)
which is equal to 1.698.
Therefore pH of 0.01 moles of H2SO4 is 1.698 or 1.70.
Hope it helps!
pH of any acid can be calculated by using the following formula:
pH= -log(H+) Here H+ refers to the concentration of H+ ions or the Hydronium ions.
Firstly we need to see the disociation of H2SO4 in water:
H2SO4(aq)————→ 2H+(aq) + (SO4)^2-(aq)
Here it can be clearly observed that 1 moles of sulphuric acid gives rise to 2 moles of H+ ions.
Therefore, 0.01 moles of H2SO4 will give rise to 0.02 moles of H+ ions
Substituting the value of H+ in the formula,
pH=-log(0.02)
which is equal to 1.698.
Therefore pH of 0.01 moles of H2SO4 is 1.698 or 1.70.
Hope it helps!
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