How to calculate if garden pea has 14 chromosomes in its diploid complement how many double trisomics could theoretically exist?
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2n = 14 in pea. This is the diploid set.
Therefore, n = 7 i.e 7 pairs of chromosomes are present.
Assuming that you already are aware about trisomy, the method to calculate the number of double trisomics that are theoretically possible is as follows:
n = 7
6+5+4+3+2+1 = 21 double trisomics.
Another example to make it clear:
In bean plants, 2n = 12. How many different double trisomics are possible?
Here, n = 6 chromosomal pairs.
Double trisomics will be:
5+4+3+2+1 = 15
Therefore, n = 7 i.e 7 pairs of chromosomes are present.
Assuming that you already are aware about trisomy, the method to calculate the number of double trisomics that are theoretically possible is as follows:
n = 7
6+5+4+3+2+1 = 21 double trisomics.
Another example to make it clear:
In bean plants, 2n = 12. How many different double trisomics are possible?
Here, n = 6 chromosomal pairs.
Double trisomics will be:
5+4+3+2+1 = 15
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