Question

How to calculate ionic strength of a 0.2m na2hpo4?

Answer 1

Hello Dear.

● Ionic strength of the solution is known as the function of all Ion present in solution.
So for calculating the Ionic strength of 0.2 M Na2HPO4

● I = $\frac{1}{2}$ ∑cîzî²

I = 1/2 [0.2M x 2 x 1² + 0.2M x 1 x (-2)²]
=1/2 [0.4 + 0.8]
=1/2 [1.2]
= 0.6 M
● Hence Ionic strength = 0.6 M.

Hope it Helps.

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