how to calculate oxidation no. of Fe in Na4[Fe(CN)6] pls explain
Answers
Answered by
0
Answer:
Na4(Fe(CN)6) is salt composed of Na+ ions as cations and the complex anion (Fe(CN)6)4-. The formal charge of this anion (4-) is equal to the algebraic sum of the oxidation numbers of the constituent atoms and /or formal charges of the group's inside; Thus, assigning -1 for CN, then
-4 = -1×6 + oxidation no of Fe
Then
Oxidation number of Fe = +2
Similar questions