Question

How to calculate perimeter of rhombus i length of diagonals are given?

Answer 1

if the length of there diagonals are give we can use the formula
(side)^2=(d1/2)^2+(d2/2)^2

Answer 2

If length of the diagonals of rhombus is given, the perimeter can be calculated as :-

1) We know that diagonals of rhombus bisect each other at 90° .

2) Now, take the half of both the diagonals.

3) Apply Pythagoras Theorem in any of the four triangles.

4) You will get the side of rhombus.

5) Calculate the perimeter, i.e., 4× side.

$\bf{\underline{For\:example}}$

Let diagonals be 16 cm and 12 cm.

Divide them by 2 .

So, AO = 16/2 = 8 cm

BO =12/2 = 6 cm

In ∆AOB

AB^2 = AO^2 +BO^2

AB^2 = 8^2 +6^2

AB^2 = 64 +36

AB^2 = 100

AB=√100

AB = 10

Perimeter of rhombus= 4×AB

=4×10

=40 cm