How to calculate pOH and pH of any substance using log?? Kindly answer fast because I am gonna give exam tomorrow...
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Answer:
POH + PH = 14
- Log (H+ ) = PH
- Log (OH-) = POH
Log values
Log 1 = 0
Log 2 = 0.3
Log 3 = 0.48
Log 4 = 0.6
Log 5 = 0.70
Log 6 = 0.78
Log 7 = 0.85
Log 8 = 0.90
Log 9 = 0.95
Log 10 = 1
Explanation:
Example if H+ = 10^-5
then PH = 5
Example if POH =4
then OH- = 10^-4
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