How to calculate stereoisomers of a compound for even numbers?
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For geometrical isomers (i.e. in case of polyenes),
If 'n' is even (here n is the number of double bonds):Number of stereoisomers=2n−1+2n/2−1.
If 'n' is odd, then: Number of stereoisomers=2n−1+2(n−1)/2.
Answered by
0
Answer:
For geometrical isomers (i.e. in case of polyenes),
1. If 'n' is even (here n is the number of double bonds):Number of stereoisomers=2n−1+2n/2−1.
2. If 'n' is odd, then: Number of stereoisomers=2n−1+2(n−1)/2.
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