Question

How to Calculate The Average Of The Cubes Of First 9 Natural Numbers ?

Answer 1

Answer:

The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2. The average of even numbers from 1 to n = (last even number+2)/2. The average of squares of first n odd numbers = (2n+1)(2n-1)/3

Answer 2

Step-by-step explanation:

First we have to finding the sum of 9 natural numbers

=1³+2³+3³+4³+5³+6³+7³+8³+9³

=1+8+27+64+125+216+343+512+729

=2,025

Average of the cubes of first 9 natural numbers=2,025/9

=225

So, the average of the cubes of first 9 natural numbers is 225.

I hope it help u to understand