Question

How to Calculate the bond enthalpy in any reactions ???​

Answer 1

Answer:

Bond enthalpy is energy required to break bonds

Hope it helps you

plzzzzzzzzz mark as brainlist

please follow me and I will follow back

Answer 2

Answer:

XY(g) → X(g) + Y(g)

ΔH° (298 K) = Dx−y

Explanation:

Examples of Bond Enthalpy Problems

Calculate the enthalpy of the reaction:

CO(g) + 2 H2(g) ⟶ CH3OH(g)

The enthalpy of the bonds in the molecule can be determined from the enthalpies of the individual bonds. For this, refer to a table such as the page given in the Resources.

You can see that there are a total of three bonds broken: The triple bond between C and O and the two H−H bonds. The total enthalpy is 1072 + 2(432) = 1,936 kJ.

The number of bonds formed is five: three C−H bonds, one C-O bond and one O−H bond. The total enthalpy of these bonds is 3(411 ) + 358 + 459 = 2,050 kJ.

Thus the total enthalpy change is 1,936 − 2,050 = −114 kJ. The negative sign shows that the reaction is exothermic, liberating rather than requiring energy to proceed.