Math, asked by copycat1315, 7 months ago

how to calculate the distance between two points on a graph { not coordinates}

Answers

Answered by utkarsh1595
2

Step-by-step explanation:

how to calculate the distance between two points on a graph { not coordinates}

ans=u have to put it on this formula

final position-initial position

Answered by jssanyam108
2

Answer:

how to calculate the distance between two points on a graph { not coordinates}

Step-by-step explanation:

how to calculate the distance between two points on a graph { not coordinates}

Quick Explanation

When we know the horizontal and vertical distances between two points we can calculate the straight line distance like this:

distance = √ a2 + b2

graph 2 points

Imagine you know the location of two points (A and B) like here.

What is the distance between them?

graph 2 points

We can run lines down from A, and along from B, to make a Right Angled Triangle.

And with a little help from Pythagoras we know that:

a2 + b2 = c2

graph 2 points

Now label the coordinates of points A and B.

xA means the x-coordinate of point A

yA means the y-coordinate of point A

The horizontal distance a is (xA − xB)

The vertical distance b is (yA − yB)

Now we can solve for c (the distance between the points):

Start with: c2 = a2 + b2

Put in the calculations for a and b: c2 = (xA − xB)2 + (yA − yB)2

Square root of both sides: c = square root of [(xA-xB)^2+(yA-yB)^2]

Done!

Examples

Example 1

graph 2 points

Fill in the values: c = square root of [(9-3)^2+(7-2)^2]

c = square root of [6^2+5^2] = square root of 61

Example 2

It doesn't matter what order the points are in, because squaring removes any negatives:

graph 2 points

Fill in the values: c = square root of [(3-9)^2+(2-7)^2]

c = square root of [(-6)^2+(-5)^2] = square root of 61

Example 3

And here is another example with some negative coordinates ... it all still works:

graph 2 points

Fill in the values: c = square root of [(-3-7)^2+(5-(-1))^2]

c = square root of [(-10)^2+(6)^2] = square root of 136

(Note √136 can be further simplified to 2√34 if you want)

Three or More Dimensions

It works perfectly well in 3 (or more!) dimensions.

Square the difference for each axis, then sum them up and take the square root:

Distance = √[ (xA − xB)2 + (yA − yB)2 + (zA − zB)2 ]

distance between (9,2,7) and (4,8,10) in 3d

Example: the distance between the two points (8,2,6) and (3,5,7) is:

= √[ (8−3)2 + (2−5)2 + (6−7)2 ]

= √[ 52 + (−3)2 + (−1)2 ]

= √( 25 + 9 + 1 )

= √35

Which is about 5.9

Question 1 Question 2 Question 3 Question 4 Question 5 Question 6 Question 7 Question 8 Question 9 Question 10

Equation of a Line from 2 Points

Algebra Index .

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