Question

how to calculate the energy needed to ionise 46(g) of Na(g)​

Answer 1

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Answer 2

We have to calculate the energy needed to ionise 46g of Na (g).

solution : Ionisation Energy is the amount of energy required to remove an electron from its isolated ground state.

so we have to find energy needed to form Na to Na⁺ ion.

from Bohr's theory,

Ionisation Energy = 13.6 × Z² eV/atom

from sodium, Z = 11

no of atoms of sodium in 46 g = mass of sodium/atomic mass of sodium × Avogadro's number

= 46g/23g × 6.023 × 10²³

= 12.046 × 10²³ atoms

now ionisation Energy of Na = 13.6 × 11² × 12.046 × 10²³ eV

we know, 1 eV = 1.6 × 10^-19 J

so, ionisation Energy of Na = 13.6 × 121 × 12.046 × 10²³ × 1.6 × 10^-19 J

= 31,716.6362 × 10⁴ J

= 3.17166362 × 10^7 J

≈ 3.17 × 10^7 J

Therefore energy needed to ionise 46 g of Na is 3.17 × 10^7 J.