Question

how to calculate the energy of second bohr's orbit of Li2+ atom in joule unit​

Answer 1

Explanation:

Answer - E = -30.6 eV. R = 0.7053 A°

◆ Explanation - Energy associated with 2nd Bohr's orbit is - E = -13.6 Z²/n² E = -13.6 × 3² / 2²

E = -30.6 eV. Radius of 2nd Bohr's orbit in Li2+ is given by - R = 0.529 n²/Z. R = 0.529 × 2² / 3.

R = 0.7053 A°

Hope it helps you out

Answer 2

Answer:

◆ Answer - E = -30.6 eV. R = 0.7053 A°

◆ Explanation - Energy associated with 2nd Bohr's orbit is - E = -13.6 Z²/n² E = -13.6 × 3² / 2²

E = -30.6 eV. Radius of 2nd Bohr's orbit in Li2+ is given by - R = 0.529 n²/Z. R = 0.529 × 2² / 3.

R = 0.7053 A°