How to calculate the equidistant coordinates between (5,-2) and (-3,2)
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Answer:
here is your answer hope you like it
tip for you: you can find it by mid point formula
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Step-by-step explanation:
Let these points be A and B respectively.
Equidistant point be P
Therefore P(x, y)
PA=PB
PA^2=PB^2
Distance is d
(x-5)^2+(y-(-2))^2=(x-(-3))^2+(y-2))^2
x^2+25+10x+y^2+4-4y=x^2+9+6x+y^2+4-4y
x^2,y^2 gets cancelled.....
29+10x-4y=13+6x-4y
16+4x-4y+4y=0
16+4x=0
x=-4
P=(-4,y)
Similarly find y...
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