How to calculate the equivalent weight of al2(so4)3
Answers
Answered by
58
Normality:
It is defined as the number of gram -equivalents of solute dissolved in one liter of solution. and designated by symbol 'N'
Normality (N) = Gram equivalent of solute / Volume of solution in liter
where, Gram equivalent is the ratio of weight of the compound to equivalent weight of the compound
Equivalent weight is Molecular weight / Z
Z is a number whose value depends on the chemical context of reaction
For salts: Z is the oxidation or valence state of the ion.
Al2(SO4)3 :
molecular weight of Al2(SO4)3 : 2 X 27 + 3 X 32 + 2X 16 =342
for Al2(SO4)3, Z=6 because 2Al+3 is equivalent to 6 moles of H+.
valence of Al2(SO4)3: 6
equivalent weight of Al2(SO4)3 : 342 / 6 = 57
1 mole Al2(SO4)3 is 342 gm
Normality of 1 mole al sulph is
57 gm eq valent / lit is 1 N solution
342 gm / lit therefore is 6 N solution
The answer is 6 N
It is defined as the number of gram -equivalents of solute dissolved in one liter of solution. and designated by symbol 'N'
Normality (N) = Gram equivalent of solute / Volume of solution in liter
where, Gram equivalent is the ratio of weight of the compound to equivalent weight of the compound
Equivalent weight is Molecular weight / Z
Z is a number whose value depends on the chemical context of reaction
For salts: Z is the oxidation or valence state of the ion.
Al2(SO4)3 :
molecular weight of Al2(SO4)3 : 2 X 27 + 3 X 32 + 2X 16 =342
for Al2(SO4)3, Z=6 because 2Al+3 is equivalent to 6 moles of H+.
valence of Al2(SO4)3: 6
equivalent weight of Al2(SO4)3 : 342 / 6 = 57
1 mole Al2(SO4)3 is 342 gm
Normality of 1 mole al sulph is
57 gm eq valent / lit is 1 N solution
342 gm / lit therefore is 6 N solution
The answer is 6 N
PindaleJatt:
hlw
Answered by
32
In Inorganic compounds like these, finding Equivalent weight is simple.
The total positive charge is given by 2Al³⁺ = 6
The total negative charge is given by 3SO₄⁻² = 6
The total positive charge = the total negative charge = n-factor = 6
And we know,
molecular weight
equivalent weight = -------------------------
n- factor
The total positive charge is given by 2Al³⁺ = 6
The total negative charge is given by 3SO₄⁻² = 6
The total positive charge = the total negative charge = n-factor = 6
And we know,
molecular weight
equivalent weight = -------------------------
n- factor
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