how to calculate the log of 3.8×10^-3
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Answered by
18
Answer:
log 2 = 0.3010
log 3 = 0.4771
log 19 = 1.2787
log 10 = 1
Here base is 10 if not mentioned.
log 3.8 can be written as log 38/10 = log 38 - log 10 by property log (a/b) = log a - log b .
log 38/10 = log 38 - log 10
= log 19*2 - log 10 [ log (a x b) = log a + log b ]
= log 19 + log 2 - log 10
= 1.2787 + 0.3010 - 1
= 0.5787
Answered by
3
Answer:
Yrr.. Hje tak log di baare ni sikhiaa...
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