how to calculate the number of water molecules present in one drop which weighs 0.18g
Answers
Answered by
0
Answer:
Molecular mass of H
O
=18g=1mole
18g of water contains 6.022×10
23
molecules.
∴0.18g of water contains, =
18
0.18×6.023×10
23
=0.06023×10
23
=6.023×10
23
molecules.
Explanation:
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Answered by
0
Answer:
Molecular mass of H =18g=1mole
18g of water contains 6.022×10^23 molecules.
∴0.18g of water contains, = 0.18×6.023×10^23/18
=0.06023×10^23
=6.023×10 ^23 molecules.
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