How to calculate the oxidation number of an element for balancing redox reaction.
Pls give an easy explanation and not the bookish language.
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for calculating ox. no. of an element in a compound....u first need to know the general oxidation no. for the remaining elements present in that particular compound.
now we know that the total charge for any compound is 0.
so, oxidation no. of the element = 0-[sum of the ( ox. no. of each element * the no. of atoms of that element in that compound)]
for ex. ox. no. of Cl in KClO3 is given by
x( ox. no. of Cl ) + 1 +(3*-2) = 0
so , x = 0- (-5)= +5
now we know that the total charge for any compound is 0.
so, oxidation no. of the element = 0-[sum of the ( ox. no. of each element * the no. of atoms of that element in that compound)]
for ex. ox. no. of Cl in KClO3 is given by
x( ox. no. of Cl ) + 1 +(3*-2) = 0
so , x = 0- (-5)= +5
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