Math, asked by amanapex1, 3 months ago

how to calculate the potential difference of 1.5 v​

Answers

Answered by Homework4Me
0

Step-by-step explanation:

Number of electron density n = 8.4 x 10. Are of cross section A = 0.3 mm2 = 0.3 x 10-6 m. Charge of electron e = 1.6 x 10-19 C. Applied electric field potential V = 1.5 V.

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