Question

How to calculate the slope of normal of an ellpise ?

Answer 1

Answer:

If m is the normal to the ellipse x2a2+y2b2=1, then the equation of normal is y=mx±m(a2-b2)√a2+b2m2.

Step-by-step explanation:

your problem's solution here.

Answer 2

Answer:

simple first of all find the eqn and differentiate it w.r.t x so u will get dy/dx (which is slopee of tangent)

thn do reciprocal of it ad put - sign

u will get -(dx/dy) which is slope if normal

this method is applicable on any random curve