Question

How to calculate the velocity in the first Bohr orbit of hydrogen atom

Answer 1

Answer:

218×10

Explanation:

2.18×10

6

m/s

The velocity of electron of the n

th

stationary state for a hydrogen-like specie is expressed as :

v

n

=2.18×10

6

×

n

Z

m/s

where Z=atomic number and n= orbit.

For First Bohr orbit of Hydrogen atom, n=1 and Z=1

thus for Hydrogen v

1

(H)=2.18×10

6

×

1

1

m/s

or the velocity of electron present in first Bohr orbit of hydrogen atom=v

1

(H)=2.18×10

6

m/s