Chemistry, asked by namannimade4901, 1 year ago

How to calculate the wave number for shortest wavelength transition in the Balmer Series of atomic Hydrogen?

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Answered by CyberAkay
37

The shortest wavelength transition in the Barlmer series corresponds to the transitionn = 2 → n = ∞. Hence, n1 = 2, n2 = ∞ Balmer
Putting the values in the equation we get, wavenumber=27419.25/cm.
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Answered by FallenLove
3

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  • The shortest wavelength transition in the Barlmer series corresponds to the transitionn = 2 → n = ∞. Hence, n1 = 2, n2 = ∞ Balmer
  • Putting the values in the equation we get, wavenumber=27419.25/cm.
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