How to calculate the wave number of a spectral line in the hydrogen spectrum?
Answers
Answered by
1
For Balmer series, n1 is 2, that is, transition takes place from n1=2 to higher energy levels, n2= 3, 4, 5, 6....... and so on.
For calculating wave number of shortest wavelength, energy difference should be large, as wavelength is inversely prpportional to each other. So transition should takes place from n1=2 to n2= ∞ .
Using the formulae: ν=1R1n12-1n22
ν= 11.09 ×107122-1∞2ν= 11.09×10714-0....... (1/∞= 0)ν=0.2294 × 10-7m-1ν= 22.94×10-9 m-1ν= 1λλ= 122.94×10-9λ= 0.0436 ×109λ= 4.36 × 107m
For calculating wave number of shortest wavelength, energy difference should be large, as wavelength is inversely prpportional to each other. So transition should takes place from n1=2 to n2= ∞ .
Using the formulae: ν=1R1n12-1n22
ν= 11.09 ×107122-1∞2ν= 11.09×10714-0....... (1/∞= 0)ν=0.2294 × 10-7m-1ν= 22.94×10-9 m-1ν= 1λλ= 122.94×10-9λ= 0.0436 ×109λ= 4.36 × 107m
Similar questions