How to calculate total energy by using power (W/m2)?
Answers
Answer:
hope this help you
Explanation:
The Sun sits in the vacuum of space and loses its energy primarily by radiation. Its most easily modeled as a black-body radiator that is at a temperature of 5778K. This means that each square meter of surface area radiates according to Stephan Boltzmann
The Sun sits in the vacuum of space and loses its energy primarily by radiation. Its most easily modeled as a black-body radiator that is at a temperature of 5778K. This means that each square meter of surface area radiates according to Stephan BoltzmannWatts/m2 = 5.67e-8 * (5778^4) = 63,196,527 Watts/m2
The Sun sits in the vacuum of space and loses its energy primarily by radiation. Its most easily modeled as a black-body radiator that is at a temperature of 5778K. This means that each square meter of surface area radiates according to Stephan BoltzmannWatts/m2 = 5.67e-8 * (5778^4) = 63,196,527 Watts/m2Now the Sun's radius is 696,342,000 meters and the Earth is 149.6e9 meters. Thus one square meter of light covers a square 214.837 meters on a side by the time it reached Earth, so the intensity at Earth has fallen from 61.2 million watts/m2 to 1,369.2 watts/m2 just above Earth's atmosphere. Of course this varies throughout the year depending on whether the Earth is at perihelion or apohelion. The atmosphere absorbs energy and reflects energy so by the time it gets to the Earth's surface the sun delivers 1,000 Watts per square meter perpendicular to the Sun's rays on a clear day near sea level.