Question

How to calculate van't hoff factor of coordination compounds?

Answer 1

It's either dissociation or association of a molecule.

If a molecule dissociates the vant Hoff factor (i) i>1

If a molecule associates then i<1.

For MgSO4 and all ionic compounds i is always greater than one theoretically, else it depends on degree of dissociation experimentally.

MgSO4----> Mg(2+) + SO4(2-)

The vant Hoff factor for MgSO4 is 2 as it dissociates completely into two ions.

Likewise for BaCl2

BaCl2----> Ba(2+) + 2Cl(1-)

So vant Hoff factor for BaCl2 is 3 as it dissociates to three ions.

Numbers in brackets indicates charge of the ion

Likewise for association,

Acetic acid in benzene

It dimerizes in benzene

CH3COOH----> (CH3COOH)2

vant Hoff factor for acetic acid is half which is less than one.

I hope I gave right answer.
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